(iii) The amount of hydrocarbon burned was 0.050 mol.
Use this information and your answers to parts (e) (i) and (e) (ii) to calculate the molecular
formula of the hydrocarbon.
If you could not answer parts (e) (i) or (e) (ii) use the values of 0.20 moles carbon dioxide
and 0.50 moles hydrogen. These are not the answers to parts (e) (i) and (e) (ii).
Formula =

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04-09-2022
Chemistry

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(iii) The amount of hydrocarbon burned was 0.050 mol.
Use this information and your answers to parts (e) (i) and (e) (ii) to calculate the molecular
formula of the hydrocarbon.
If you could not answer parts (e) (i) or (e) (ii) use the values of 0.20 moles carbon dioxide
and 0.50 moles hydrogen. These are not the answers to parts (e) (i) and (e) (ii).
Formula =

Sagot :

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