Answered

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You have 379,200 grams of a radioactive kind of samarium. How much will be left after 450 years if its half-life is 90 years?

Sagot :

The equation for the amount left after t years if half life is

[tex]t_{\frac{1}{2}}[/tex]

and initial amount is A is,

[tex]A^{\prime}=A(\frac{1}{2})^{\frac{t_{}}{t_{\frac{1}{2}}}}[/tex]

Determine the amount left after 450 years.

[tex]\begin{gathered} A=379200\times(\frac{1}{2})^{\frac{450}{90}} \\ =379200\times(\frac{1}{2})^5 \\ =11850 \end{gathered}[/tex]

Thus amount of samarium left after 450 years is 11850 grams.

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