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Sagot :
Answer
For [H+] ---> pH = 6.2
For [OH-] ---> pH = 1.53
Explanation
Given:
[H+]=6.27x10^-7M
[OH-]=3.4x10^-13
Required: Calculate pH
Solution:
[tex]pH\text{ = -log\lbrack H}_3O^+][/tex]For [H+]=6.27x10^-7M
pH = -log[6.27x10^-7]
pH = 6.2
For [OH-]=3.4x10^-13
14 = pH + pOH
pH = 14 + log[OH-]
pH = 14 + log [3.4x10^-13]
pH = 1.53
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