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4.5 ft wide and 6 feet long and 2 ft longer and 1.5 feet wider. how do I solve this

Sagot :

[tex]B)48\text{ sq ft}[/tex]

Explanation

the area of a rectangle is given by:

[tex]A_{rec\tan gle}=length\cdot width[/tex]

Step 1

Set the new measures

[tex]\begin{gathered} \text{length}_{new}=6+2=8\text{ ft} \\ \text{width}_{new}=4.5+1.5=6\text{ ft} \end{gathered}[/tex]

Step 2

replace in the formula to find the new area

[tex]\begin{gathered} A_{rec\tan gle}=length\cdot width \\ A_{rec\tan gle}=8\text{ ft}\cdot\text{ 6 ft} \\ A_{rec\tan gle}=48\text{ sq ft} \\ \end{gathered}[/tex]

so,the answer is

[tex]B)48\text{ sq ft}[/tex]

I hope this helps you

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