I am getting 223g of C6H6. I understand the way this problem was solved, however, the teacher is giving a different equation for us to use. The equation is:

Amount Given x (1 mol given/molar mass) x ((y) mol sought/(x) mol given) x (molar mass/1 mol sought) = Answer

x and y are coefficients of the given substance from balanced equation.
Molar mass can be replaced with particles and L if needed based on the question

I am getting very different answers and not sure what next.

Question

Whyiseverythingadsidn Whyiseverythingadsidn

01-12-2022
Chemistry

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I am getting 223g of C6H6. I understand the way this problem was solved, however, the teacher is giving a different equation for us to use. The equation is:

Amount Given x (1 mol given/molar mass) x ((y) mol sought/(x) mol given) x (molar mass/1 mol sought) = Answer

x and y are coefficients of the given substance from balanced equation.
Molar mass can be replaced with particles and L if needed based on the question

I am getting very different answers and not sure what next.

Sagot :

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