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Using the distance of the 1998KY 26 in the small angle equation, we find: angular speed in "/sec/206265 ′′ = linear speed in meters/sec/4.35×10 9 m Compute the linear speed of 1998KY 26 in meters per second and note the answer below. Show your work
5. What is the value below closest to the speed of the 1998KY 26 you computed above?
a) 100 meters/second d) 5000 meters/second b) 1100 meters/second e) 10000 meters/second c) 2000 meters/second
Sagot :
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