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A projectile launched vertically from an altitude of h0 feet with an initial velocity of v0 feet per second. The height of the projectile is h(t) feet after t seconds is given by h(t)=−16t2+v0t+h0 If h(1)=143 and h(2)=179, find the values of v0 and h0. v0= h0=
Sagot :
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