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AERONAUTICS At liftoff, the space
shuttle Discovery has a constant
acceleration of 16.4 feet per second
squared and an initial velocity of
1341 feet per second due to the rotation
of Earth. The distance Discovery has
traveled t seconds after liftoff is given by
the equation d(t) = 1341t + 8.2t^2 How
long after liftoff has Discovery traveled
40,000 feet? Round your answer to the
nearest tenth.
Sagot :
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