Muhammadqadeer4472idn
Answered

Find solutions to your questions with the help of IDNLearn.com's expert community. Join our Q&A platform to get accurate and thorough answers to all your pressing questions.

For reactions in the gas phase, an equilibrium constant may be written in terms of molarity (Kc) or in terms of partial pressures (Kp).
The value of Kc for the reaction shown below is equal to 2.9×10⁻⁴ at 298K.
2 NOBr(g) ⇄ 2NO(g) + Br₂(g)
What is the value for Kp at 298K for the reaction represented by the equation shown below? The value for the gas constant, R, is 0.08206 L . atm/mol. K.
NOBr(g) ⇄ NO}(g) + 1/2 Br₂(g)

For Reactions In The Gas Phase An Equilibrium Constant May Be Written In Terms Of Molarity Kc Or In Terms Of Partial Pressures Kp The Value Of Kc For The Reacti class=

Sagot :

We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.