The active ingredient in a Tum® antacid tablet i calcium carbonate (CaCO 3, FM = 100. 09), it neutralize exce hydrochloric acid (HCl, FM = 36. 46) in the tomach via the reaction CaCO 3 () 2HCl(aq) → CaCl 2 (aq) H 2 O(l) CO 2 (g). A certain doe of Tum containing 750 mg of CaCO 3 i added to 25 mL of 0. 100 M HCl. What i the volume of CO 2 generated under condition of STP?

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07-12-2022
Chemistry

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The active ingredient in a Tum® antacid tablet i calcium carbonate (CaCO 3, FM = 100. 09), it neutralize exce hydrochloric acid (HCl, FM = 36. 46) in the tomach via the reaction CaCO 3 () 2HCl(aq) → CaCl 2 (aq) H 2 O(l) CO 2 (g). A certain doe of Tum containing 750 mg of CaCO 3 i added to 25 mL of 0. 100 M HCl. What i the volume of CO 2 generated under condition of STP?

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