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Solve the following differential equation. (dy)/(dt) + (2ty)/(1+t²) = 4ty
a) y = ((2t² + (4/3)t⁶ + C) / (1 + t²)²) b) y = ((2/3)(1 + t²)³ + C) / (1 + t²)² c) y = (1(1 + t²)² + C) / (1 + t²) d) y = ((4/3)t⁶ + C) / (1 + t²)
Sagot :
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