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Suppose that aₖ ≥ 0, bₖ ≥ 0 for all k ≥ 1. Prove that if ∑[infinity]ₖ₌₁ aₖ and ∑[infinity]ₖ₌₁ bₖ converge, then ∑[infinity]ₖ₌₁ aₖbₖ also converges.
Sagot :
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