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A testcross of AaBb gives 30% aaBb progeny. What percentage of the progeny will be Aabb or aaBb if the same plant is self-fertilized? Show your work and circle your answer.
Because that AaBb produces 30% of aB gamete, the genotype must be aB/Ab, and the map distance between A and B is 40 mu Ab = aB = 30% AB = ab = 20%
p(Ab/ab) + p(aB/ab) = 4 x (0.3 x 0.2) = 0.24 = 24%
Explain and show how this answer was acquired.
Sagot :
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