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Let the eccentricity of the hyperbola x 2 a 2 − y 2 b 2 = 1 be reciprocal to that of the ellipse x 2 + 4 y 2 = 4 . lf the hyperbola passes through a focus of the ellipse, then the equation of the hyperbola is x 2 3 − y 2 2 = 1 a focus of the hyperbola is ( 2 , 0 ) the equation of the hyperbola is x 2 − 3 y 2 = 3 the eccentricity of the hyperbola is √ 5 3 be obtained by heating?
Sagot :
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