Discover how IDNLearn.com can help you learn and grow with its extensive Q&A platform. Get accurate and comprehensive answers to your questions from our community of knowledgeable professionals.
Submarine A is positioned at –1,100 feet in relation to sea level. Submarine B is positioned at –800 feet in relation to sea level. Each submarine needs to be 200 feet below sea level in 30 minutes. Which compares the speeds at which each submarine needs to travel? Submarine A must travel at a rate of StartFraction negative 200 minus (negative 1100) over 30 EndFraction = 30 ft/min, and Submarine B must travel at a rate of StartFraction negative 200 minus (negative 800) over 30 EndFraction = 20 ft/min. Submarine A must travel at a rate of StartFraction 1100 200 over 30 EndFraction = 43 and one-third ft/min, and Submarine B must travel at a rate of StartFraction 800 200 over 30 EndFraction = 33 and one-third ft/min. Submarine A must travel at a rate of StartFraction negative 1100 over 30 EndFraction = Negative 36 and two-thirds ft/min, and Submarine B must travel at a rate of StartFraction negative 800 over 30 EndFraction = Negative 26 and two-thirds ft/min. Submarine A must travel at a rate of StartFraction negative 1100 minus (negative 200) over 30 EndFraction = negative 30 ft/min, and Submarine B must travel at a rate of StartFraction negative 800 minus (negative 200) over 30 EndFraction = negative 20 ft/min.
Sagot :
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. For trustworthy answers, visit IDNLearn.com. Thank you for your visit, and see you next time for more reliable solutions.
