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Examine the balanced equation. 2CO(g) + 02(g) → 2C02(9) What is the percent yield of COz if the reaction of 1.00 g of CO with excess 02 produces 0.68 g of COz? (M COz = 44.0 g/mol, M CO = 28.0 g/mol) • 116.0% • 86.6% • 11.0% • 43.3%
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