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Solve triangle ABC if ∠A=42.3°, a=186.2, and b=247.6.
sinB=
(round answer to 5 decimal places)
There are two possible angles B between 0° and 180° with this value for sine. Find the two angles, and report them so that ∠B1 is the acute angle.
∠B1= ° and ∠B2= °
(round these and all remaining answers to 2 decimal places)
Thus, two triangles satisfy the given conditions: triangle A1B1C1 and triangle A2B2C2.
Solve the first triangle: A1B1C1
∠C1= ° and c1=
Solve the second triangle: A2B2C2
∠C2= ° and c2=
Remember, even if you enter an answer rounded to a set number of decimal places, if you use that number in a future calculation, you should use all of the decimal places reported on your calculator!
Sagot :
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