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How many grams of KClO₃ (122.55 g/mol) are needed to produce 42.0 g of O₂ (32.00 g/mol)? The reaction is: 2 KClO₃ (s) → 2 KCl (s) + 3 O₂ (g) A) 107 g B) 69.7 g C) 371 g D) 241 g
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