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The solution to the standing wave equation for a stretched string is of the form ψ(z,t)= Asin(kz)cos(ωt+φ) and the total energy density of the standing wave is given by W(z,t)= 1/2μ(∂ψ/∂t)²+1/2T(∂ψ/∂z)² where T is the tension in the ring and μ is its linear mass density (a) Show that the maximum kinetic density of an antimode on the string is given by 1/2μw²A². (b) Show rhat the maximum potential energy of a node on the string is 1/2TK²A²
Sagot :
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