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the attached document is the exact question that i am stumped on.



Triangle ABC has vertices A(−3, 1), B(−3, 4), and C(−7, 1).



Part A: If ∆ABC is translated according to the rule (x, y) → (x − 3, y + 4) to form ∆A'B'C', how is the translation described with words? (3 points)
Part B: Where are the vertices of ∆A'B'C' located? Show your work or explain your steps. (4 points)
Part C:Triangle A'B'C' is rotated 180° counterclockwise about the origin to form ∆A"B"C". Is ∆ABC congruent to ∆A"B"C"? Give details to support your answer. (3 points)


this is the copy and paste, but the formatting is slightly off.

Please answer ASAP time crunch! 2nd time asking because i am in dire need of this.

The Attached Document Is The Exact Question That I Am Stumped On Triangle ABC Has Vertices A3 1 B3 4 And C7 1 Part A If ABC Is Translated According To The Rule class=

Sagot :

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