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What is the pressure (in atm) in a 1.25 L container of argon gas, Ar, that contains 40.0 g of the gas at 30.0°C? 1000 mL = 1 L ºC + 273.15 = K 760 mm Hg = 1 atm - 1.96 atm - 0.0502 atm - 796 atm - 19.93 atm
Sagot :
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