What is the pressure (in atm) in a 1.25 L container of argon gas, Ar, that contains 40.0 g of the gas at 30.0°C?
1000 mL = 1 L
ºC + 273.15 = K
760 mm Hg = 1 atm
- 1.96 atm
- 0.0502 atm
- 796 atm
- 19.93 atm

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11-08-2024
Chemistry

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What is the pressure (in atm) in a 1.25 L container of argon gas, Ar, that contains 40.0 g of the gas at 30.0°C?
1000 mL = 1 L
ºC + 273.15 = K
760 mm Hg = 1 atm
- 1.96 atm
- 0.0502 atm
- 796 atm
- 19.93 atm

Sagot :

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