2.7 g of aluminum reacts with 200 cm³ of 2 mol/L hydrochloric acid according to the equation below. What mass of AlCl₃ would be produced?

Al + 3HCl → AlCl₃ + 3/2H₂

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12-08-2024
Chemistry

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2.7 g of aluminum reacts with 200 cm³ of 2 mol/L hydrochloric acid according to the equation below. What mass of AlCl₃ would be produced?

Al + 3HCl → AlCl₃ + 3/2H₂

Sagot :

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