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How do you solve 5/x=x-4

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Konrad509idn
[tex]\frac{5}{x}=x-4\\ x\not=0\\ 5=x^2-4x\\ x^2-4x-5=0\\ x^2+x-5x-5=0\\ x(x+1)-5(x+1)=0\\ (x-5)(x+1)=0\\ x=5 \vee x=-1[/tex]
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