LissaPacific818idn
Answered

Get detailed and accurate responses to your questions on IDNLearn.com. Get the information you need from our community of experts, who provide detailed and trustworthy answers.

A force F of strength 20 N acts on an object of mass 3 kg as it moves a distance of 4 m. If F is perpendicular to the 4 m displacement, the work it does is equal to how many joules?

Sagot :

Mashenkaidn
Data:
[tex] F = 20 [N] [/tex]
[tex] m = 3 [kg] [/tex]
[tex] s = 4 [m] [/tex]
Work is calculated from the following formula:
[tex] W = F \cdot s \cdot cos(a) [/tex]
Where a is the angle between force vector and displacement vector. When force is perpendicular to displacement, a = 90 deg and cosine of this angle = 0.
Therefore, the work this force does = 0 [J]
AL2006idn
Work = (displacement) x (force in the direction of the displacement)

Since none of the force is in the direction of the displacement, the work it does
is zero. Something else is making the object move.  It's not the 20N force.
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Thank you for visiting IDNLearn.com. We’re here to provide accurate and reliable answers, so visit us again soon.