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What is square root of 126 + square root of 56 in standard form

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Mariamikaylaidn
[tex]\sqrt{126}= 3\sqrt{14} \\ \\ \sqrt{56}=2\sqrt{14} \\ \\ \\ \sqrt{126}+ \sqrt{56}= 3\sqrt{14}+2\sqrt{14}= 5\sqrt{14}[/tex]
[tex]\sqrt{126}+\sqrt{56}=\sqrt{9\times14}+\sqrt{4\times14}=\sqrt9\times\sqrt{14}+\sqrt4\times\sqrt{14}\\\\=3\sqrt{14}+2\sqrt{14}=5\sqrt{14}[/tex]
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