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A scientist wants to raise the temperature of a 0.10-kilogram sample of glass from –45°C to 15°C. How much heat energy is required to produce this change in temperature?

Sagot :

Luanaidn
[tex]Formula\ for\ heat\ energy:\\\\ Q=mCp(T_2-T_1)\\\\ m-mass=0,1kg\\Cp-specific\ heat\ of\ glass=800\frac{J}{kgC^{\circ}}\\T_2=15^{\circ}\\T_1=-45^{\circ}\\\\ Q=0,1*800(15+45)=80*60=4800J\\\\4800J\ is\ required\ to\ heat\ this\ glass.[/tex]
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