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AngleDFG and angleJKL are complementary angles. M angleDFG =x+5, and m angleJKL=x-9. Find the measure of each angle

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[tex]Measures\ of\ complementary\ angles\ make\ sum\ equal\ to\ 90^{\circ}.\\\\ \angle DFG+\angle JKL=90^{\circ}\\\\ x+5+x-9=90\\\\ 2x=90-5+9\\\\ 2x=94\ \ \ |:2\\\\x=47^{\circ}\\\\ \angle DFG=x+5=47+5=52^{\circ}\\ \angle JKL=x-9=47-9=38^{\circ}[/tex]
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