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What is 4(3q - 2) = 16q

Sagot :

[tex]4(3q-2)=16q\\\\12q-8=16q\ \ \ \ \ \ |add\ 8\ to\ both\ sides\\\\12q=16q+8\ \ \ \ \ \ |subtract\ 16q\ from\ both\ sides\\\\-4q=8\ \ \ \ \ \ \ |divide\ both\ sides\ by\ (-4)\\\\\boxed{q=-2}[/tex]
Mashenkaidn
[tex] 4\cdot (3q - 2) =16q[/tex]
We first multiply the expression in parentheses by 4:
[tex] 4\cdot 3q - 4\cdot 2 = 16q [/tex]
[tex] 12 q - 8 = 16 q [/tex]
Then, we move expression with q to the left hand side and constant to the right hand side:
[tex] 12q - 16q = 8 [/tex]
[tex] -4q = 8 [/tex]
We divide both sides by (-2):
[tex] q = -2 [/tex]
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