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The mass of a subway car and it's passengers is 40,000 kg. if it's acceleration as it leaves the station is 0.9 m/s^2, what is the net force acting on it?

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To answer this problem, we have to employ Newton's Second Law of Motion, or F = ma. F is the force in Newtons (N) where as m is mass (kg) and a is the acceleration (m/s^2). An easy plug in will give us

F = ma
F = (40,000 kg.)(0.9 m/s^2)
F = 36,000 N.

The answer is 36,000 N. Good luck!
Nuhulawal20idn

The net force acting on the subway car and it's passengers is 3.6 × 10⁴ Newton.

Given the data in the question;

  • Mass of a subway car and it's passengers; [tex]m = 40000 kg[/tex]
  • Acceleration as it leaves the station; [tex]a = 0.9 m/s^2[/tex]

Net force; [tex]F = \ ?[/tex]

From Newton's second law of Motion:

[tex]F = m\ *\ a[/tex]

Where F is the force, m is mass of object and a is the acceleration.

We substitute our given values into the equation

[tex]F = 40000kg\ *\ 0.9m/s^2\\\\F = 36000 kg.m/s^2\\\\F = 3.6*10^4N[/tex]

Therefore, the net force acting on the subway car and it's passengers is 3.6 × 10⁴ Newton.

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