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Jika log2= 0,3010
log3= 0,4771
maka log (3√2x√3) =

Sagot :

Crisforpidn
log (3√2x√3) = log( 3 * [tex] 3^{1/2} [/tex]* x * [tex] 2^{1/2} [/tex] ) = log( [tex] 3^{3/2} [/tex] * x * [tex] 2^{1/2} [/tex] ) = log(  [tex] 3^{3/2} [/tex]) + log x + log( [tex] 2^{1/2} [/tex] ) = ( 3 / 2 ) * 0,4771 + log x + ( 1 / 2 ) * 0,3010 = 0,7156 + 0,1505 + log x = 0, 8661 + log x.
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