Mossowidn
Answered

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Starting at a certain speed, a bicyclist travels 200m. Suppose the bicyclist undergoes a constant acceleration of 1.20m/s squared. If the final speed is 25.0m/s, what was the bicyclists initial speed?

Sagot :

V2^2 = V1^2 + 2*a* s
V2 = final velocity
V1 = initial velocity
a   = acceleration
s   = displacement covered
25^2 = V1^2 + 2 * 1.2 * 200
625  = V1^2  + 480
625 - 480 = V1^2
145          = V1^2
So V1 = Sqrt(145) = 12.04 m/s
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