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A balloon holds 20.0 liters of helium at 10.0°C. If the temperature increases to 50.0°C, and the pressure does
not change, what will be the new volume of the balloon?
Volum at the beginning: [tex]V_{1}=10[/tex] Volum at the end: [tex]V_{2}=V_{1}*(1+ \alpha* (t_{2}-t_{1}))[/tex] [tex]t_{2}-t_{1}=50-10=40[/tex] α for helium = [tex]0,003658\frac{1}{C}[/tex] As the result you get: [tex]V_{2}=20*(1+0,003658*40)=22,9264 l[/tex] Final volume of the balloon is 22,9264 liters.
(Only if it doesn't explode during being heated ;) just a joke)
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