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Solving systems of equations by substitution
Y=6x y=5x+7
First substitute 'y' in 2nd equation by right side of 1st one and you get: [tex]Y=6x[/tex] [tex]6x=5x+7[/tex] now substract 5x from both sides of 2nd equal and you get: [tex]6x-5x=5x+7-5x[/tex] as a result of the equal above you get: [tex]x=7[/tex] now substitute x in very first equation by the result from above (x=7): [tex]Y=6*7=42[/tex] [tex]x=7[/tex]
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