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find the midpoint between each (8, -9) and (8, 5)

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Crisforpidn
( 8 + 8 ) / 2 = 8;  ( - 9 + 5 ) / 2 = -2 => ( 8, -2 ).
[tex]The\ formula\ of\ midpoint\ between\ (x_1;\ y_1)\ and\ (x_2;\ y_2)\\\\\left(\frac{x_1+x_2}{2};\ \frac{y_1+y_2}{2}\right)\\\\===================================\\(8;-9);\ (8;\ 5)\\\\\left(\frac{8+8}{2};\ \frac{-9+5}{2}\right)\to\left(\frac{16}{2};\ \frac{-4}{2}\right)\to\fbox{(8;-2)}[/tex]
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