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The sum of three consecutive odd numbers is 153 what is the smallest of the three numbers?
[tex]n+(n+2)+(n+4)=153[/tex] -- combine like terms [tex]3n+6=153[/tex] -- subtract 6 from both sides [tex]3n=147[/tex] -- divide by 3 [tex]n=49[/tex]
So the numbers are 49, (49+2) and (49+4) I.e. 49, 51, and 53 But the question only wants the smallest (i.e. the first of the consecutive odd numbers). The smallest of the 3 consecutive odd numbers that sum to 153 is 49
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