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Find two consecutive even integers such that the lesser added to three times the greater gives a sum of 46.

Sagot :

n; n + 2 - the two consecutive even integers

n + 3(n + 2) = 46
n + 3n + 6 = 46    |subtract 6 from both sides
4n = 40        |divide both sides by 4
n = 10

n + 2 = 10 + 2 = 12

Answer: 10 and 12.
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