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Sagot :
[tex]1h=60min\to1min=\frac{1}{60}h\\\\\\345\ ft/min=345\ \frac{ft}{\frac{1}{60}h}=345\times60\ ft/h=20,700\ ft/h[/tex]
the rate given is 345 ft/min
this means within 1 min distance is - 345 ft
we have to convert this speed to ft/h
1 hour is equivalent to 60 minutes
so if 60 minutes equals 1 hour
1 minute is equal to - 1/60 hr
so the distance within 1 minute is - 345 ft
since 1 min = 1/60 hr
distance within 1/60 hour = 345 ft
therefore distance in 1 hour = [tex] \frac{345}{1/60} = 345 * 60 = 20 700 ft [/tex]
answer is 20 700 ft/h
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