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The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the first number. Find the integers.
I hate math.


Sagot :

[tex]x-first\ number\\3x-second\ number\\2x-10-third\ number\\\\2+3x+2x-10=92\\\\3x+2x=92-2+10\\\\5x=100\ \ \ \ \ \ \ \ |:5\\\\x=20\\3x=3\cdot20=60\\2x-10=2\cdot20-10=30[/tex]

Answer:

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