Reever56idn
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Find 3x2 - y3 - y3 - z if x = 3, y = -2, and z = -5.

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Illuminati750idn
Hello, 

[tex]3 x^{2} -y^{3} -y^{3}-z \\ =3 x^{2} -2y^{3}-z \\ \\ Replacing:\,\, \,\,x=3\,\, \,\,y=-2\,\, \,\,z=-5 \\ \\ =3(3)^{2} -2(-2)^{3}-(-5) \\ =3*9-2*(-8)+5 \\ =27+16+5 \\ =48[/tex]

Answer: 48

Answer:

The value of [tex]3x^2-y^3-y^3-z[/tex]  is, 48

Step-by-step explanation:

Given the equation:

Let f(x, y, z) = [tex]3x^2-y^3-y^3-z[/tex]           .....[1]

Like terms states that the terms which have the same variables.

Combine like terms in equation [1];

[tex]f(x, y, z) =3x^2-2y^3-z[/tex]                            ......[2]

Given: x= 3 , y= -2 and z = -5.

Substitute these given values in [2] we get;

[tex]f(3, -2, -5) =3(3)^2-2(-2)^3-(-5)[/tex]

[tex]f(3, -2, -5) =3(9)-2(-8)-(-5)[/tex] = 27 + 16 +5 = 48.

Therefore, the value of [tex]3x^2-y^3-y^3-z[/tex]  is, 48


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