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A triangle has height 4 ft and area 32 ft2. What is the lenght of the base?

Sagot :

[tex]A=32ft^2 \\\\ A=\frac{b*h}{2} \\\\ \frac{b*4}{2}=32 \\\\ b=\frac{2*32}{4} \\\\ b=2*8 \\\\ \boxed{b=16ft}[/tex]
[tex]Formula\ for\ area\ of\ triangle:\\\\ Area=\frac{1}{2}base*height\\\\ 32=\frac{1}{2}*4*base\\\\ 32=2base\ \ \ |Divide\ by\ 2\\\\ base=16ft\\\\ Length\ of\ base\ is\ equal\ to\ 16ft.[/tex]