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The length of a rectangle is 7 yd less than three times the width, and the area of the rectangle is 66 yd ^2. Find the dimensions of the rectangle

Sagot :

Luanaidn
[tex]x-\ width\\ (3x-7)\ -\ length\\\\ Formula \ for\ area\ of\ rectangle:\\Area=2length+2width\\\\ 66=2x+2(3x-7)\\ 66=2x+6x-14\\ 66=8x-14\ \ \ |Add\ 14\\ 80=8x\ \ \ |Divide\ by\ 8\\ x=10\\ 3x-7=3*10-7=30-7=23\\\\Dimensions:\\ length: 23yd\\ width:10yd.[/tex]
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