IDNLearn.com connects you with a community of knowledgeable individuals ready to help. Our community is here to provide the comprehensive and accurate answers you need to make informed decisions.
Sagot :
P = 2( L + W )
-divide both sides by 2
P/2 = L + W
-subtract L from both sides
P/2 - L = W
or
(P - L) / 2 = W
-divide both sides by 2
P/2 = L + W
-subtract L from both sides
P/2 - L = W
or
(P - L) / 2 = W
Hello,
We know that if we make the same operation on both sides, we don't affect the equation:
For example:
[tex]2=2 \\ 2\bold{+2}=2\bold{+2} \\ 4=4[/tex]
Do you see? we add 2 on both sides and we don't affect the equality
We can do the same with the multiplication, for example
4=4 (i'll multiply both sides by 1/2)
[tex]4*\bold{ \frac{1}{2}}=4*\bold{ \frac{1}{2}} \\ 2=2[/tex]
Now, we do exactly the same in your excercise:
[tex]P=2(L+W) \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,[multiply\,\,by\,\,1/2] \\ \\ P*\bold{ \frac{1}{2}}=2(L+W)*\bold{ \frac{1}{2}} \\ \\ \frac{P}{2}=L+W\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,[Subtract\,\,L]\\ \\ \frac{P}{2}-\bold{L}=L+W-\bold{L}\\ \\ \frac{P}{2}-\bold{L}=L-\bold{L}+W \\ \\ \frac{P}{2}-L=W\\ \\ \boxed{ W= \frac{P}{2}-L }[/tex]
We know that if we make the same operation on both sides, we don't affect the equation:
For example:
[tex]2=2 \\ 2\bold{+2}=2\bold{+2} \\ 4=4[/tex]
Do you see? we add 2 on both sides and we don't affect the equality
We can do the same with the multiplication, for example
4=4 (i'll multiply both sides by 1/2)
[tex]4*\bold{ \frac{1}{2}}=4*\bold{ \frac{1}{2}} \\ 2=2[/tex]
Now, we do exactly the same in your excercise:
[tex]P=2(L+W) \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,[multiply\,\,by\,\,1/2] \\ \\ P*\bold{ \frac{1}{2}}=2(L+W)*\bold{ \frac{1}{2}} \\ \\ \frac{P}{2}=L+W\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,[Subtract\,\,L]\\ \\ \frac{P}{2}-\bold{L}=L+W-\bold{L}\\ \\ \frac{P}{2}-\bold{L}=L-\bold{L}+W \\ \\ \frac{P}{2}-L=W\\ \\ \boxed{ W= \frac{P}{2}-L }[/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.