Find the best solutions to your problems with the help of IDNLearn.com's expert users. Get accurate and detailed answers to your questions from our knowledgeable and dedicated community members.
Sagot :
18-11=7 to find out how much halve the water weight
then subtract 7 from 11 11-7=4
so the emtpy bucket weighs 4 kg
[tex]x-weights \ the \ bucket \\ y-weights \ the \ water \\\\ x+y=18 =>\boxed{x=18-y} \\ x+\frac{y}{2}=11 \\\\ 18^{(2}-y^{(2}+\frac{y}{2}=11^{(2} \\\\ 36-2y+y=22 \\\\ 36-y=22 \\\\ -y=22-36 \\\\ -y=-14 \\\\ \boxed{y=14 kg} \\\\ x=18-14 \\\\ \boxed{x=4kg}[/tex]
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and see you next time for more reliable information.