Answered

Join IDNLearn.com and start getting the answers you've been searching for. Our platform provides detailed and accurate responses from experts, helping you navigate any topic with confidence.

Suppose y varies directly as x, and y =16 when x=8. Find y when x=16

Sagot :

Logo88idn
 y varies directly as x, and y =16 when x=8. Find y when x=16
y is double x
so when x=16
y=16x2 which equals 32
Carlosegoidn

For this case, since the variation is direct then we have a relation of the form:

[tex] y = kx
[/tex]

Where,

k: proportionality constant

To find k we substitute the following data:

y = 16 when x = 8

We have then:

[tex] 16 = k8
[/tex]

Clearing the value of k we have:

[tex] k = \frac{16}{8}

k = 2
[/tex]

Then, the equation is:

[tex] y = 2x
[/tex]

Substituting the value of x = 16 we have:

[tex] y = 2 (16)

y = 32
[/tex]

Answer:

The value of y for x = 16 is:

[tex] y = 32 [/tex]

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. IDNLearn.com provides the answers you need. Thank you for visiting, and see you next time for more valuable insights.