using special products what is (wx-y)^2

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24-02-2014
Mathematics

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using special products what is (wx-y)^2

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Priyambaksiidn Priyambaksiidn · Answer 1 · 2014-02-24T22:05:22-05:00

Priyambaksiidn Priyambaksiidn

24-02-2014

i think that supposed to be (wx - y^2)^2?

If so, multiply using FOIL:

First: wx * wx = w^2x^2

Outside: wx * -y^2 = -wxy^2

Inside: -y * wx = -wxy^2

Last: -y^2 * -y^2 = y^4

Combine w^2x^2 - 2wxy^2 + y^4

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Isaacrosado04idn Isaacrosado04idn · Answer 2 · 2020-10-29T13:45:55-04:00

Isaacrosado04idn Isaacrosado04idn

29-10-2020

Answer:

I believe it is wx^2 - 2ywx + y^2

Step-by-step explanation:

seperated into (wx-y)(wx-y) and used FOIL

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