Emilybb195idn
Answered

Get detailed and accurate responses to your questions on IDNLearn.com. Ask anything and receive prompt, well-informed answers from our community of experienced experts.

The temperature of a sample of water increases from 20°C to 46°C as it absorbs 5650 calories of heat. What is the mass of the sample? (Specific heat of the water is 1.0 Cal/g °C

Sagot :

Luanaidn
[tex]Formula\ for\ specific\ heat:\\\\ c=\frac{\Delta\ Q}{m*\Delta t}\\ c-\ specific\ heat\\ m-\ mass\\ \Delta Q-\ change\ of\ calories\\ \Delta T-\ change\ of\ temperature\\\\ 1=\frac{5650}{m(46-20)}\\\\ 1=\frac{5650}{26m}\ \ \ |*26m\\\\ 26m=5650\ \ \ |:26\\\\ m=217,3\ grams\\\\ Sample\ weight\ 217,3\ grams.[/tex]
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for trusting IDNLearn.com. We’re dedicated to providing accurate answers, so visit us again for more solutions.