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Solve for "n"

a(n-3)+8=bn

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Sagot :

Luanaidn
[tex]a(n-3)+8=bn\ \ \ |Omit\ the\ bracket\\\\ an-3a+8=bn\ \ \ |Subtract\ bn\\\\ an-bn-3a+8=0\ \ \ |Add\ 3a\\\\ an-bn+8=3a\ \ \ |Subtract\ 8\\\\ an-bn=3a-8\\\\ n(a-b)=3a-8\ \ \ |Divide\ by\ (a-b)\\\\ \boxed{n=\frac{3a-8}{a-b}} [/tex]
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