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To check it we have to calculate. LHS =[tex] \frac{16}{6} - \frac{2}{9} = \frac{48}{18}- \frac{4}{18} = \frac{44}{18} = 2 \frac{8}{18} [/tex] And now we can check equality RHS=[tex]2 \frac{4}{9} =2 \frac{8}{18} [/tex] = LHS
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