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5x^2+19x+12 factor the polynomial

Sagot :

Crisforpidn
Δ = 19^2 - 4*5*12 => Δ = 121 => [tex] \sqrt{delta} [/tex] = 11;
x1 = -0.8; x2 = -3;
5x^2+19x+12 = 5( x + 0.8)( x + 3) = ( 5x + 4)( x + 3);
Anaiscineusidn

Answer:

( x − 3 )( 5x − 4 )

Step-by-step explanation:

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