Answered

From personal advice to professional guidance, IDNLearn.com has the answers you seek. Ask your questions and receive detailed and reliable answers from our experienced and knowledgeable community members.

6x-2y=33
4x+3y=9 What would x and y be?

Sagot :

Mariamikaylaidn
[tex]6x-2y=33 \\\\ 6x=33+2y \\\\ \boxed{x=\frac{2y+33}{6}} \\\\ 4x+3y=9 \\\\ 4*\frac{2y+33}{6}+3y=9 \\\\ 2*\frac{2y+33}{3}+3y^{(3}=9^{(3} \\\\ 2(2y+33)+9y=27 \\\\ 4y+66+9y=27 \\\\ 13y=27-66 \\\\ 13y=- 39 \\\\ \boxed{y=-\frac{39}{13}=-3} \\\\ x=\frac{2*(-3)+33}{6} \\\\ x=\frac{-6+33}{6} \\\\ x=\frac{27}{6} \\\\ \boxed{x=\frac{9}{2}}[/tex]
Johnweshasidn
To find the variables of the equations, use systems of equations.

First get rid of one variable. Let's get rid of the y by multiplyin both equations nad then adding them.
[tex](6x-2y=33)3[/tex]
[tex](4x+3y=9)2[/tex]

[tex]18x-6y=99[/tex]
[tex]8x+6y=18[/tex]
[tex]26x=117[/tex]

Solve for x:
[tex] \frac{26x}{26} = \frac{117}{26} [/tex]
[tex]x=4.5[/tex]

Now you have x! Plug x into one quation and solve for y:
[tex]6(4.5)-2y=33[/tex]
[tex]27-2y=33[/tex]
[tex] \frac{-2y}{-2} = \frac{6}{-2} [/tex]
[tex]y=-3[/tex]

[tex]x=4.5, y=-3[/tex]
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.