Answered

Find answers to your most challenging questions with the help of IDNLearn.com's experts. Discover detailed answers to your questions with our extensive database of expert knowledge.

6x-2y=33
4x+3y=9 What would x and y be?

Sagot :

Mariamikaylaidn
[tex]6x-2y=33 \\\\ 6x=33+2y \\\\ \boxed{x=\frac{2y+33}{6}} \\\\ 4x+3y=9 \\\\ 4*\frac{2y+33}{6}+3y=9 \\\\ 2*\frac{2y+33}{3}+3y^{(3}=9^{(3} \\\\ 2(2y+33)+9y=27 \\\\ 4y+66+9y=27 \\\\ 13y=27-66 \\\\ 13y=- 39 \\\\ \boxed{y=-\frac{39}{13}=-3} \\\\ x=\frac{2*(-3)+33}{6} \\\\ x=\frac{-6+33}{6} \\\\ x=\frac{27}{6} \\\\ \boxed{x=\frac{9}{2}}[/tex]
Johnweshasidn
To find the variables of the equations, use systems of equations.

First get rid of one variable. Let's get rid of the y by multiplyin both equations nad then adding them.
[tex](6x-2y=33)3[/tex]
[tex](4x+3y=9)2[/tex]

[tex]18x-6y=99[/tex]
[tex]8x+6y=18[/tex]
[tex]26x=117[/tex]

Solve for x:
[tex] \frac{26x}{26} = \frac{117}{26} [/tex]
[tex]x=4.5[/tex]

Now you have x! Plug x into one quation and solve for y:
[tex]6(4.5)-2y=33[/tex]
[tex]27-2y=33[/tex]
[tex] \frac{-2y}{-2} = \frac{6}{-2} [/tex]
[tex]y=-3[/tex]

[tex]x=4.5, y=-3[/tex]
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Thank you for visiting IDNLearn.com. We’re here to provide dependable answers, so visit us again soon.